1Hand speedsminute: 6∘/min,hour: 0.5∘/minthe minute hand gains 5.5∘ a minute
2Angle at H hours M minutesθ=∣30H−5.5M∣θ>180∘⇒use 360∘−θ
3Hands mirrored across 12-6θh+θm=360∘θh=30H+0.5M,θm=6M
4Together after H o'clockM=1160Hmin past Hevery 65115min: 11 times in 12 hours
5Hands θ apart after H o'clockM=112(30H±θ)min past Hθ=angle wanted; keep 0≤M<60
6Right angles in a dayRight angles come every 32118 min: 22 in 12 hours, 44 a day, not 48. The one at 3 o'clock serves both 2 to 3 and 3 to 4, and the same at 9.
7True time on a fast clockclock time passedtrue time passed=60+g60g=min gained per true hour,g<0 if slow
8Faulty clock from its handsAny clock's hands meet every 65115 min of its own time. If they meet every T true minutes, a smaller T means it runs fast: it gains 65115−T min per T.
9Striking clockn strokes have n - 1 gaps, and the time goes with the gaps: 5 strokes in 8 seconds means 2 seconds a gap.
Test yourself
10 questions · 3 easy · 4 medium · 3 hard
Tap an option to answer. The first tap counts.
Q1Easy
How many degrees does the hour hand of a clock turn between 9 am and 1:30 pm on the same day?
Correct answer·135∘
Why
Hour-hand speed: 30∘ an hour, which is 0.5∘ a minute.
From 9 am to 1:30 pm is 4.5 hours, and 4.5×30=135.
So the hour hand turns through 135∘.
Q2Easy
What is the smaller angle between the hands of a clock at 8:20?
Correct answer·130∘
Why
Use the angle formula ∣30H−5.5M∣.
∣30×8−5.5×20∣=∣240−110∣=130; leaving the hour hand fixed on the 8 gives the trap 120∘.
So the smaller angle is 130∘.
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