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LearnQuantitative AptitudeNumber System

02.05 · Number System

Unit Digit & Cyclicity

Elite lesson11 formulas10 questions

On the syllabus of

Elite lesson22 minHindi

Formulas

At a glance 11 formulas

  1. 1Last digit onlyOnly the units digit of the base matters: 1287n1287^{n} ends like 7n7^{n}. In a sum or product, combine just the units digits.
  2. 2Units-digit cycles
    0, 1, 5, 6
    itself, always
    4
    4, 6
    9
    9, 1
    2
    2, 4, 8, 6
    3
    3, 9, 7, 1
    7
    7, 9, 3, 1
    8
    8, 4, 2, 6
  3. 3Exponent mod 4an ends like ar, r=n mod 4a^{n} \text{ ends like } a^{r},\ r = n \bmod 4r=0⇒ends like a4r = 0 \Rightarrow \text{ends like } a^{4}
  4. 4Quick remainder by 4Only the last two digits of the exponent decide its remainder by 4: for 2027, 27=24+327 = 24 + 3 gives 3.
  5. 5DifferencesIf the larger number has the smaller units digit, borrow 10: a number ending in 4 minus one ending in 5 ends in 14−5=914 - 5 = 9.
  6. 6Products with a 5A product with a factor 5 and any even factor ends in 0; a 5 times only odd numbers ends in 5.
  7. 7Sums of factorialsn! ends in 0 for n≥5n! \text{ ends in } 0 \text{ for } n \ge 51!+2!+3!+4!=331! + 2! + 3! + 4! = 33
  8. 8Remainder by 10The remainder by 10 is the units digit; by 5 or by 2, it is that digit's own remainder by 5 or 2.
  9. 9Cycle sum is 20The four units digits in one cycle of 2, 3, 7 or 8 add to 20, so in a+a2+⋯+ana + a^{2} + \cdots + a^{n} only the terms left after full fours count.
  10. 10Power of a powerIn abca^{b^{c}} find bc mod 4b^{c} \bmod 4 first: b≡1b \equiv 1 gives 1, b≡3b \equiv 3 gives 3 for odd cc and 1 for even cc, and even bb gives 0 once c≥2c \ge 2.
  11. 11Last two digitsReach a power that ends in 01, then reduce: 74=24017^{4} = 2401 and 3203^{20} ends in 01, so 74k7^{4k} and 320k3^{20k} end in 01.

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    What is the units digit of 8438^{43}?

    Correct answer2

    Why

    Powers of 8 end in 8, 4, 2, 6, and the pattern repeats every 4.

    43=40+343 = 40 + 3, so take the 3rd ending in the cycle.

    So 8438^{43} ends in 2.

  2. Q2Easy

    Asked in BBA DBE 2024

    The digit in the units' place of 132003−729113^{2003} - 7^{291} is ___.

    Correct answer4

    Why

    Cut each exponent to its remainder by 4 and keep units digits only.

    The exponents 2003 and 291 are both 3 more than a multiple of 4, so the two numbers end like 33=273^{3} = 27 and 73=3437^{3} = 343, in 7 and 3.

    13200313^{2003} dwarfs 72917^{291} and 7 minus 3 needs no borrow, so the units digit is 4.

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