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LearnQuantitative AptitudeNumber System

02.06 · Number System

Remainders & Remainder Theorems

Elite lesson12 formulas10 questions

On the syllabus of

Elite lesson30 minEnglish

Formulas

At a glance 12 formulas

  1. 1Division ruleN=dq+r,0≤r<dN = dq + r,\quad 0 \le r < d
  2. 2Work with remaindersa≡r, b≡s⇒ab≡rsa \equiv r,\ b \equiv s \Rightarrow ab \equiv rsa+b≡r+s,an≡rna + b \equiv r + s,\quad a^{n} \equiv r^{n}
  3. 3Negative remaindersa≡−1(modd)⇒an≡(−1)na \equiv -1 \pmod d \Rightarrow a^{n} \equiv (-1)^{n}a remainder of −r means d−r\text{a remainder of } {-r} \text{ means } d - r
  4. 4Remainder on a factorIf NN leaves rr when divided by dd, and ff divides dd, then NN leaves the remainder of rr by ff: 47 by 60 means 11 by 12.
  5. 5Digit remaindersRemainder by 9 (or 3) is the digit sum's remainder; by 4 or 8, the last 2 or 3 digits'; by 11, the alternating digit sum's, counted from the units digit.
  6. 6Same remainder, many divisorsN=k⋅LCM(a,b,c)+rN = k \cdot \text{LCM}(a, b, c) + rsame shortfall g: N=k⋅LCM−g\text{same shortfall } g\text{: } N = k \cdot \text{LCM} - g
  7. 7Power that leaves ±1ak≡1⇒an≡a n mod ka^{k} \equiv 1 \Rightarrow a^{n} \equiv a^{\,n \bmod k}ak≡−1⇒a2k≡1a^{k} \equiv -1 \Rightarrow a^{2k} \equiv 1
  8. 8Fermat's little theoremap−1≡1(modp)a^{p-1} \equiv 1 \pmod pp prime, p∤ap \text{ prime},\ p \nmid a
  9. 9Sums of powers(a+b)∣an+bn for odd n(a + b) \mid a^{n} + b^{n} \text{ for odd } n(a−b)∣an−bn for every n(a - b) \mid a^{n} - b^{n} \text{ for every } n
  10. 10Twice the numberIf NN leaves rr and 2N2N leaves ss on division by the same dd, then dd divides 2r−s2r - s, and dd is more than rr.
  11. 11Cancel a common factorIf the number and the divisor share a factor kk, cancel it, find the remainder, then multiply that remainder back by kk.
  12. 12Split the divisorFor a big divisor, split it into co-prime parts, like 7 and 9 for 63, find the remainder by each, then pick the number below the divisor that fits both.

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    What is the remainder when 71×73×7671 \times 73 \times 76 is divided by 7?

    Correct answer4

    Why

    Remainders multiply, so swap each number for its remainder by 7.

    71, 73 and 76 leave 1, 3 and 6, and 1×3×6=181 \times 3 \times 6 = 18.

    18=14+418 = 14 + 4, so the remainder is 4.

  2. Q2Easy

    What is the remainder when 533753^{37} is divided by 27?

    Correct answer26

    Why

    Use a negative remainder: 53=54−153 = 54 - 1 and 54=2×2754 = 2 \times 27, so 53≡−1(mod27)53 \equiv -1 \pmod{27}.

    37 is odd, so (−1)37=−1(-1)^{37} = -1.

    A remainder of −1-1 means 27−1=2627 - 1 = 26.

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