1SelectionsnCr=r!(n−r)!n!r chosen from n;nCr=nCn−r
2Select, then arrangenPr=nCr×r!pick the r from n first, then order them
3Always in, always outk always in: n−kCr−kk always out: n−kCr;r chosen from n
4From two groupsaCx×bCyx from a group of a,y from a group of b
5At least kFor 'at least k', add the cases k, k + 1 and so on; if those are many, take all selections minus the few that fail. Any number, at least one, from n different things: 2n−1.
6A pair never togethernCr−n−2Cr−2r from n;two named people never together
7Splitting into groupsa!b!c!(a+b+c)!sizes a,b,c;k equal unnamed groups: ÷k!
8Nobody left outDifferent items to k people, each getting at least one: split the items into k non-empty bundles, then hand them out in k! ways. 4 prizes, 3 people: 6×3!=36.
9Handshakes and diagonalsnC2=2n(n−1)n people;n-gon diagonals: 2n(n−3)
10Collinear pointstriangles=nC3−mC3m of the n collinear;lines=nC2−mC2+1
11Rectangles on a gridm+1C2×n+1C2m×n grid;squares: mn+(m−1)(n−1)+⋯
12Triangles from a polygonFrom the n corners of a polygon: nC3 triangles, of which n share two sides with it and n(n−4) share exactly one.
Test yourself
10 questions · 3 easy · 4 medium · 3 hard
Tap an option to answer. The first tap counts.
Q1Easy
In a college cricket league, each of 9 teams plays every other team exactly once. How many matches are played in all?
Correct answer·36
Why
Each match is a pair of teams, and a pair has no order: 9C2.
29×8=36; the 72 counts every match twice, once from each side.
So 36 matches are played.
Q2Easy
A committee of 5 is to be chosen from 10 students. Neha must be on it and Ravi must not. In how many ways can the committee be chosen?
Correct answer·70
Why
Must be in, must be out: seat Neha on the committee and strike Ravi off the list.
That leaves 4 places to fill from the other 8 students: 8C4=248×7×6×5.
So there are 70 ways.
8 more questions: 1 easy, 4 medium, 3 hard
Sign in free to see all ten and get your score. No payment, no card.