2Smallest and largest overlapmax(0,a+b−N)≤n(A∩B)≤min(a,b)a,b,c=set sizes,N=total;all three≥a+b+c−2N
3Three setsn(A∪B∪C)=S1−S2+S3S1=n(A)+n(B)+n(C),S2=Σpairs,S3=all three
4Exactly twoexactly two=Σpairs−3×all threeat least two=Σpairs−2×all three
5Exactly oneexactly one=S1−2S2+3S3S1=n(A)+n(B)+n(C),S2=Σpairs,S3=all three
6Count by membershipn(A)+n(B)+n(C)=E1+2E2+3E3Ek=in exactly k sets;union=E1+E2+E3
7Fill from the centreDraw the three circles and fill the all-three region first, then each pair minus it, then each 'only' region, and the 'none' outside last.
8Extremes: crowd or spreadFor the largest 'none' or overlap, crowd people into the overlaps; for the smallest, spread them out. Every region must stay 0 or more.
9Subsets and relationsn(A)=k⇒2k subsetsrelations from A to B=2n(A)×n(B)
10Element by elementCount pairs of subsets of a k-element set element by element: for A⊆B each element is in neither, in B only, or in both, so 3k pairs.
Test yourself
10 questions · 3 easy · 4 medium · 3 hard
Tap an option to answer. The first tap counts.
Q1Easy
At a college fest, 52 students signed up for the quiz, 38 signed up for the debate and 15 signed up for both. How many students signed up for at least one of the two events?
Correct answer·75
Why
Use the two-set rule: n(A∪B)=n(A)+n(B)−n(A∩B).
52+38=90 counts the 15 who signed up for both twice, so take them away once: 90−15=75.
So 75 students signed up for at least one event.
Q2Easy
Set A has 3 elements and set B has 4 elements. How many different relations from A to B are there?
Correct answer·4,096
Why
A relation from A to B is any subset of A×B.
A×B has 3×4=12 ordered pairs, and each pair is either in the relation or out of it.
So there are 212=4096 relations.
8 more questions: 1 easy, 4 medium, 3 hard
Sign in free to see all ten and get your score. No payment, no card.