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05.01 · Modern Maths

Sets & Venn Diagrams

Open lesson10 formulas10 questions

On the syllabus of

Formulas

At a glance 10 formulas

  1. 1Two setsn(A∪B)=n(A)+n(B)−n(A∩B)n(A \cup B) = n(A) + n(B) - n(A \cap B)neither=total−n(A∪B)\text{neither} = \text{total} - n(A \cup B)
  2. 2Smallest and largest overlapmax⁡(0, a+b−N)≤n(A∩B)≤min⁡(a,b)\max(0,\ a + b - N) \le n(A \cap B) \le \min(a, b)a,b,c=set sizes, N=total; all three≥a+b+c−2Na, b, c = \text{set sizes},\ N = \text{total};\ \text{all three} \ge a + b + c - 2N
  3. 3Three setsn(A∪B∪C)=S1−S2+S3n(A \cup B \cup C) = S_1 - S_2 + S_3S1=n(A)+n(B)+n(C), S2=Σ pairs, S3=all threeS_1 = n(A) + n(B) + n(C),\ S_2 = \Sigma\,\text{pairs},\ S_3 = \text{all three}
  4. 4Exactly twoexactly two=Σ pairs−3×all three\text{exactly two} = \Sigma\,\text{pairs} - 3 \times \text{all three}at least two=Σ pairs−2×all three\text{at least two} = \Sigma\,\text{pairs} - 2 \times \text{all three}
  5. 5Exactly oneexactly one=S1−2S2+3S3\text{exactly one} = S_1 - 2S_2 + 3S_3S1=n(A)+n(B)+n(C), S2=Σ pairs, S3=all threeS_1 = n(A) + n(B) + n(C),\ S_2 = \Sigma\,\text{pairs},\ S_3 = \text{all three}
  6. 6Count by membershipn(A)+n(B)+n(C)=E1+2E2+3E3n(A) + n(B) + n(C) = E_1 + 2E_2 + 3E_3Ek=in exactly k sets; union=E1+E2+E3E_k = \text{in exactly } k \text{ sets};\ \text{union} = E_1 + E_2 + E_3
  7. 7Fill from the centreDraw the three circles and fill the all-three region first, then each pair minus it, then each 'only' region, and the 'none' outside last.
  8. 8Extremes: crowd or spreadFor the largest 'none' or overlap, crowd people into the overlaps; for the smallest, spread them out. Every region must stay 0 or more.
  9. 9Subsets and relationsn(A)=k⇒2k subsetsn(A) = k \Rightarrow 2^{k} \text{ subsets}relations from A to B=2 n(A)×n(B)\text{relations from } A \text{ to } B = 2^{\,n(A) \times n(B)}
  10. 10Element by elementCount pairs of subsets of a kk-element set element by element: for A⊆BA \subseteq B each element is in neither, in BB only, or in both, so 3k3^{k} pairs.

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    At a college fest, 52 students signed up for the quiz, 38 signed up for the debate and 15 signed up for both. How many students signed up for at least one of the two events?

    Correct answer75

    Why

    Use the two-set rule: n(A∪B)=n(A)+n(B)−n(A∩B)n(A \cup B) = n(A) + n(B) - n(A \cap B).

    52+38=9052 + 38 = 90 counts the 15 who signed up for both twice, so take them away once: 90−15=7590 - 15 = 75.

    So 75 students signed up for at least one event.

  2. Q2Easy

    Set AA has 3 elements and set BB has 4 elements. How many different relations from AA to BB are there?

    Correct answer4,096

    Why

    A relation from AA to BB is any subset of A×BA \times B.

    A×BA \times B has 3×4=123 \times 4 = 12 ordered pairs, and each pair is either in the relation or out of it.

    So there are 212=40962^{12} = 4096 relations.

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