1Height h, distance dh=dtanθ,θ=elevationd=hcotθ,also the shadow
2Depression equals elevationThe angle of depression from A to B equals the angle of elevation from B to A (alternate angles), so a look down uses the same right triangle.
3Handy angle factsAt 45∘ the height equals the distance. Since tan60∘=3tan30∘, an object is 3 times as far away when seen at 30∘ as at 60∘.
4Walking towards ith=cotα−cotβdd=walk in;elevation α rises to β
5Opposite sidesh=cotα+cotβdd=gap;elevations α,β from either side
6Complementary elevationsh=xyelevations θ,90∘−θ at distances x,y
7Split at eye levelH=h(1+tanβtanα)H=tower,h=eye level;top α,foot β
8Pole on a roofpole=d(tanβ−tanα)d=distance;roof at α,tip at β
9Steady approachFor an object moving straight at the foot at a steady speed, the distance left is hcotθ, so times are in the ratio of the drops in cotθ; h cancels.
10Cloud and its reflectionH=htanβ−tanαtanβ+tanαH=cloud,h=eye;cloud α,image β
11South and eastPoints due south and due east of a tower are hcotα and hcotβ from its foot, so they are hcot2α+cot2β apart (Pythagoras on the ground).
Test yourself
10 questions · 3 easy · 4 medium · 3 hard
Tap an option to answer. The first tap counts.
Q1Easy
From a point on level ground 40 m from the foot of a temple tower, the angle of elevation of its top is 60∘. How tall is the tower?
Correct answer·403 m
Why
Height is level distance times the tangent of the elevation.
h=40×tan60∘=40×3; using tan30∘ by mistake gives the trap 340.
The tower is 403≈69.3 m tall.
Q2Easy
Asked in IPMAT Indore 2024
The angle of elevation of the top of a pole from a point A on the ground is 30∘. The angle of elevation changes to 45∘ after moving 20 meters towards the base of the pole. Then the height of the pole, in meters is
Correct answer·10(3+1)
Why
At 45∘ the pole is as far away as it is tall, so call both h; at 30∘ the gap is h3.
The 20 m walk is the difference: h3−h=20, so h=3−120.
Multiply top and bottom by 3+1: the pole is 10(3+1) m tall.
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