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LearnQuantitative AptitudeGeometry & Mensuration

04.07 · Geometry & Mensuration

Coordinate Geometry: Circles & Curves

Elite lesson11 formulas10 questions

On the syllabus of

Elite lesson27 minHinglish

Formulas

At a glance 11 formulas

  1. 1Centre and radius(x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2centre (h,k), radius r\text{centre } (h, k),\ \text{radius } r
  2. 2General formx2+y2+2gx+2fy+c=0x^2 + y^2 + 2gx + 2fy + c = 0centre (−g,−f), r=g2+f2−c\text{centre } (-g, -f),\ r = \sqrt{g^2 + f^2 - c}
  3. 3Circle on a diameter(x−a)(x−c)+(y−b)(y−d)=0(x - a)(x - c) + (y - b)(y - d) = 0ends (a,b),(c,d); 90∘ at P⇒P on it\text{ends } (a, b), (c, d);\ 90^\circ \text{ at } P \Rightarrow P \text{ on it}
  4. 4Where (x₁, y₁) liesS1=x12+y12+2gx1+2fy1+cS_1 = x_1^2 + y_1^2 + 2gx_1 + 2fy_1 + cS1<0 inside, =0 on, >0 outsideS_1 < 0 \text{ inside},\ = 0 \text{ on},\ > 0 \text{ outside}
  5. 5Line d from centred<r cuts, d=r touchesd < r \text{ cuts},\ d = r \text{ touches}d>r misses; chord=2r2−d2d > r \text{ misses};\ \text{chord} = 2\sqrt{r^2 - d^2}
  6. 6Nearest and farthest pointnearest=∣d−r∣, farthest=d+r\text{nearest} = |d - r|,\ \text{farthest} = d + rd=distance from the point to the centred = \text{distance from the point to the centre}
  7. 7Tangents from Plength=d2−r2=S1\text{length} = \sqrt{d^2 - r^2} = \sqrt{S_1}d=P to centre; sin⁡θ2=rd, θ at Pd = P \text{ to centre};\ \sin\tfrac{\theta}{2} = \tfrac{r}{d},\ \theta \text{ at } P
  8. 8Two circlesCentres dd apart: d>r1+r2d > r_1 + r_2 gives 4 common tangents, d=r1+r2d = r_1 + r_2 gives 3, in between gives 2, d=∣r1−r2∣d = |r_1 - r_2| gives 1, and less gives none.
  9. 9Circle and the axesWith centre (h,k)(h, k), the circle touches the x-axis when r=∣k∣r = |k| and the y-axis when r=∣h∣r = |h|; it stays clear of both when rr is less than both.
  10. 10Fixed ratio of distancesIf PA:PB=kPA : PB = k with k≠1k \ne 1, PP traces a circle; the two points dividing ABAB in k:1k : 1, inside and outside, are the ends of a diameter.
  11. 11Circle meets a curveSubstitute to get one equation in yy (or xx). Each root gives two points, or one if the other coordinate is 0 (a touch), or none if its square is negative.

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    What is the centre of the circle x2+y2+6x−16y−27=0x^2 + y^2 + 6x - 16y - 27 = 0?

    Correct answer(−3,8)(-3, 8)

    Why

    Halve the xx and yy coefficients and flip their signs: x2+y2+2gx+2fy+c=0x^2 + y^2 + 2gx + 2fy + c = 0 has centre (−g,−f)(-g, -f).

    Here 2g=62g = 6 and 2f=−162f = -16, so g=3g = 3 and f=−8f = -8; forgetting to flip gives the trap (3,−8)(3, -8).

    The centre is (−3,8)(-3, 8).

  2. Q2Easy

    Asked in IPMAT Indore 2025

    A circle touches the yy-axis at (0,4)(0, 4) and passes through the point (−2,0)(-2, 0). Then the radius of the circle is

    Correct answer5

    Why

    Touching the yy-axis at (0,4)(0, 4) puts the centre level with it, at (−r,4)(-r, 4), on the side of (−2,0)(-2, 0).

    Its distance to (−2,0)(-2, 0) is rr: (r−2)2+42=r2(r - 2)^2 + 4^2 = r^2, so 20−4r=020 - 4r = 0.

    That makes the radius 5.

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