9Altitude to hypotenuseh=caba,b=legs,c=hypotenuse
10Similar trianglessides in ratio k⇒areas in k2DE∥BC:DBAD=ECAE;D,E on AB,AC
11Same heightTriangles with a common apex and bases on one line have areas in the ratio of their bases, so a median cuts a triangle into two equal halves.
12Angle bisector theoremDCBD=ACABAD bisects ∠A,D on BC
13Median AD, centroid GAB2+AC2=2(AD2+BD2)D=midpoint of BC;AG:GD=2:1
14Median as half sideIf the median from A is half of BC, the midpoint of BC is equally far from A, B and C, so ∠A=90∘. The converse holds too.
Test yourself
10 questions · 3 easy · 4 medium · 3 hard
Tap an option to answer. The first tap counts.
Q1Easy
Which of these sets of lengths, in cm, cannot be the sides of a triangle?
Correct answer·6,7,14
Why
Triangle inequality: the two shorter sides must add to more than the longest.
4+5>8, 5+6>10 and 7+8>12 all pass, but 6+7=13 falls short of 14.
So 6, 7, 14 cannot form a triangle.
Q2Easy
A cyclist rides 20 km due east and then 21 km due north. How far is she from her starting point, in a straight line?
Correct answer·29 km
Why
Spot the triplet 20, 21, 29.
The two legs of the ride meet at a right angle, so the distance is 400+441=841; adding the legs gives the trap 41.
So she is 29 km from the start.
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