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LearnQuantitative AptitudeGeometry & Mensuration

04.04 · Geometry & Mensuration

Quadrilaterals & Areas

Elite lesson11 formulas10 questions

On the syllabus of

Elite lesson39 minEnglish

Formulas

At a glance 11 formulas

  1. 1ParallelogramOpposite sides are equal and parallel, opposite angles are equal, neighbouring angles add to 180∘180^\circ, and the diagonals bisect each other.
  2. 2Parallelogram areabase×height=absin⁡θ\text{base} \times \text{height} = ab\sin\thetaa,b=sides, θ=angle between thema, b = \text{sides},\ \theta = \text{angle between them}
  3. 3Parallelogram diagonalsd12+d22=2(a2+b2)d_1^2 + d_2^2 = 2(a^2 + b^2)d1,d2=diagonals, a,b=sidesd_1, d_2 = \text{diagonals},\ a, b = \text{sides}
  4. 4Rhombus and squarearea=12d1d2 (d1,d2 diagonals)\text{area} = \tfrac{1}{2} d_1 d_2\ (d_1, d_2 \text{ diagonals})side2=d12+d224; square, diagonal d: d22\text{side}^2 = \tfrac{d_1^2 + d_2^2}{4};\ \text{square, diagonal } d:\ \tfrac{d^2}{2}
  5. 5Trapeziumarea=12(a+b)h, h=height\text{area} = \tfrac{1}{2}(a + b)h,\ h = \text{height}a,b=parallel sides; diagonals cut a:ba, b = \text{parallel sides};\ \text{diagonals cut } a : b
  6. 6Any quadrilateralarea=12d1d2sin⁡θ\text{area} = \tfrac{1}{2} d_1 d_2 \sin\thetad1,d2=diagonals, θ between themd_1, d_2 = \text{diagonals},\ \theta \text{ between them}
  7. 7Triangles at the diagonalsAOB×COD=BOC×DOAAOB \times COD = BOC \times DOAleast total=(AOB+COD)2\text{least total} = \left(\sqrt{AOB} + \sqrt{COD}\right)^2
  8. 8Between the same parallelsA triangle on the same base as a parallelogram, with its third corner on the opposite side, has half the parallelogram's area.
  9. 9Midpoint quadrilateralJoining the midpoints of any quadrilateral's sides in order gives a parallelogram with sides half the diagonals and half the area.
  10. 10Square in a squareinner area=a2+b2\text{inner area} = a^2 + b^2a,b=the two parts of each sidea, b = \text{the two parts of each side}
  11. 11Trapezium, perpendicular diagonalsarea=h2=(a+b2)2\text{area} = h^2 = \left(\tfrac{a + b}{2}\right)^2isosceles: a,b=parallel sides, h=height\text{isosceles: } a, b = \text{parallel sides},\ h = \text{height}

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    A square has a diagonal of 10 cm. What is its area?

    Correct answer50 sq cm

    Why

    A square is a rhombus, so its area is half the product of its diagonals: d22\frac{d^2}{2}.

    1022=50\frac{10^2}{2} = 50; squaring the diagonal alone gives the trap 100.

    So the area is 50 sq cm.

  2. Q2Easy

    In parallelogram ABCD, ∠A\angle A is 40∘40^\circ more than ∠B\angle B. What is ∠C\angle C?

    Correct answer110∘110^\circ

    Why

    Neighbouring angles of a parallelogram add to 180∘180^\circ, and opposite angles are equal.

    ∠A+∠B=180\angle A + \angle B = 180 with a gap of 40 gives ∠A=110∘\angle A = 110^\circ and ∠B=70∘\angle B = 70^\circ.

    ∠C\angle C is opposite ∠A\angle A, so ∠C=110∘\angle C = 110^\circ.

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