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Elite lesson· 39 min English Unlock every lessonFormulas At a glance 11 formulas
1 Parallelogram Opposite sides are equal and parallel, opposite angles are equal, neighbouring angles add to 180 ∘ 180^\circ 18 0 ∘ , and the diagonals bisect each other. 2 Parallelogram area base × height = a b sin θ \text{base} \times \text{height} = ab\sin\theta base × height = ab sin θ a , b = sides , θ = angle between them a, b = \text{sides},\ \theta = \text{angle between them} a , b = sides , θ = angle between them 3 Parallelogram diagonals d 1 2 + d 2 2 = 2 ( a 2 + b 2 ) d_1^2 + d_2^2 = 2(a^2 + b^2) d 1 2 + d 2 2 = 2 ( a 2 + b 2 ) d 1 , d 2 = diagonals , a , b = sides d_1, d_2 = \text{diagonals},\ a, b = \text{sides} d 1 , d 2 = diagonals , a , b = sides 4 Rhombus and square area = 1 2 d 1 d 2 ( d 1 , d 2 diagonals ) \text{area} = \tfrac{1}{2} d_1 d_2\ (d_1, d_2 \text{ diagonals}) area = 2 1 d 1 d 2 ( d 1 , d 2 diagonals ) side 2 = d 1 2 + d 2 2 4 ; square, diagonal d : d 2 2 \text{side}^2 = \tfrac{d_1^2 + d_2^2}{4};\ \text{square, diagonal } d:\ \tfrac{d^2}{2} side 2 = 4 d 1 2 + d 2 2 ; square, diagonal d : 2 d 2 5 Trapezium area = 1 2 ( a + b ) h , h = height \text{area} = \tfrac{1}{2}(a + b)h,\ h = \text{height} area = 2 1 ( a + b ) h , h = height a , b = parallel sides ; diagonals cut a : b a, b = \text{parallel sides};\ \text{diagonals cut } a : b a , b = parallel sides ; diagonals cut a : b 6 Any quadrilateral area = 1 2 d 1 d 2 sin θ \text{area} = \tfrac{1}{2} d_1 d_2 \sin\theta area = 2 1 d 1 d 2 sin θ d 1 , d 2 = diagonals , θ between them d_1, d_2 = \text{diagonals},\ \theta \text{ between them} d 1 , d 2 = diagonals , θ between them 7 Triangles at the diagonals A O B × C O D = B O C × D O A AOB \times COD = BOC \times DOA A O B × C O D = B O C × D O A least total = ( A O B + C O D ) 2 \text{least total} = \left(\sqrt{AOB} + \sqrt{COD}\right)^2 least total = ( A O B + C O D ) 2 8 Between the same parallels A triangle on the same base as a parallelogram, with its third corner on the opposite side, has half the parallelogram's area. 9 Midpoint quadrilateral Joining the midpoints of any quadrilateral's sides in order gives a parallelogram with sides half the diagonals and half the area. 10 Square in a square inner area = a 2 + b 2 \text{inner area} = a^2 + b^2 inner area = a 2 + b 2 a , b = the two parts of each side a, b = \text{the two parts of each side} a , b = the two parts of each side 11 Trapezium, perpendicular diagonals area = h 2 = ( a + b 2 ) 2 \text{area} = h^2 = \left(\tfrac{a + b}{2}\right)^2 area = h 2 = ( 2 a + b ) 2 isosceles: a , b = parallel sides , h = height \text{isosceles: } a, b = \text{parallel sides},\ h = \text{height} isosceles: a , b = parallel sides , h = height Test yourself Q1 Easy
A square has a diagonal of 10 cm. What is its area?
A 25 sq cm B 50 sq cm C 75 sq cm D 100 sq cm
Correct answer· 50 sq cm
Why
A square is a rhombus, so its area is half the product of its diagonals: d 2 2 \frac{d^2}{2} 2 d 2 .
10 2 2 = 50 \frac{10^2}{2} = 50 2 1 0 2 = 50 ; squaring the diagonal alone gives the trap 100.
So the area is 50 sq cm.
Q2 Easy
In parallelogram ABCD, ∠ A \angle A ∠ A is 40 ∘ 40^\circ 4 0 ∘ more than ∠ B \angle B ∠ B . What is ∠ C \angle C ∠ C ?
A 40 ∘ 40^\circ 4 0 ∘ B 70 ∘ 70^\circ 7 0 ∘ C 90 ∘ 90^\circ 9 0 ∘ D 110 ∘ 110^\circ 11 0 ∘
Correct answer· 110 ∘ 110^\circ 11 0 ∘
Why
Neighbouring angles of a parallelogram add to 180 ∘ 180^\circ 18 0 ∘ , and opposite angles are equal.
∠ A + ∠ B = 180 \angle A + \angle B = 180 ∠ A + ∠ B = 180 with a gap of 40 gives ∠ A = 110 ∘ \angle A = 110^\circ ∠ A = 11 0 ∘ and ∠ B = 70 ∘ \angle B = 70^\circ ∠ B = 7 0 ∘ .
∠ C \angle C ∠ C is opposite ∠ A \angle A ∠ A , so ∠ C = 110 ∘ \angle C = 110^\circ ∠ C = 11 0 ∘ .
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