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LearnQuantitative AptitudeGeometry & Mensuration

04.03 · Geometry & Mensuration

Circles & Circle Theorems

Elite lesson11 formulas10 questions

On the syllabus of

Elite lesson26 minEnglish

Formulas

At a glance 11 formulas

  1. 1Chord and centre(chord2)2+d2=r2\left(\tfrac{\text{chord}}{2}\right)^2 + d^2 = r^2r=radius, d=centre to chordr = \text{radius},\ d = \text{centre to chord}
  2. 2Tangent lengthtangent=d2−r2\text{tangent} = \sqrt{d^2 - r^2}r=radius, d=point to centrer = \text{radius},\ d = \text{point to centre}
  3. 3Equal tangentsThe two tangents from an outside point are equal. So an incircle cuts each side of a triangle into tangent lengths, and a quadrilateral with an incircle has AB+CD=BC+DAAB + CD = BC + DA.
  4. 4Chords, secants through PPA×PB=PC×PDPA \times PB = PC \times PDtangent PT: PT2=PA×PB\text{tangent } PT:\ PT^2 = PA \times PB
  5. 5Tangents, centres D apartdirect=D2−(r1−r2)2\text{direct} = \sqrt{D^2 - (r_1 - r_2)^2}transverse=D2−(r1+r2)2\text{transverse} = \sqrt{D^2 - (r_1 + r_2)^2}
  6. 6Angle at the centre∠AOB=2∠ACB; semicircle: 90∘\angle AOB = 2\angle ACB;\ \text{semicircle: } 90^\circO=centre, C on the major arcO = \text{centre},\ C \text{ on the major arc}
  7. 7Same segmentAngles that stand on the same arc, from points on the same side of its chord, are equal.
  8. 8Cyclic quadrilateral∠A+∠C=∠B+∠D=180∘\angle A + \angle C = \angle B + \angle D = 180^\circexterior angle=interior opposite angle\text{exterior angle} = \text{interior opposite angle}
  9. 9Alternate segmentThe angle between a tangent and a chord at the point of contact equals the angle that chord makes at the circle on the other side.
  10. 10Regions and sectorsJoin the centre to where the circle crosses the figure, then add or subtract triangles and sectors (θ360πr2\frac{\theta}{360} \pi r^2 for angle θ\theta, radius rr).
  11. 11Right-triangle incirclearea=BD×DC\text{area} = BD \times DC∠A=90∘, incircle touches BC at D\angle A = 90^\circ,\ \text{incircle touches } BC \text{ at } D

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    A chord 30 cm long is at a distance of 8 cm from the centre of a circle. What is the radius of the circle?

    Correct answer17 cm

    Why

    The perpendicular from the centre halves the chord, so half the chord, the distance and the radius form a right triangle.

    The legs are 15 and 8, the triplet 8-15-17.

    So the radius is 17 cm.

  2. Q2Easy

    A, B and C are points on a circle with centre O, and C lies on the major arc AB. If ∠AOB=116∘\angle AOB = 116^\circ, what is ∠ACB\angle ACB?

    Correct answer58∘58^\circ

    Why

    The angle at the centre is twice the angle at the circumference on the same arc.

    1162=58\frac{116}{2} = 58; a point on the minor arc would see 180−58=122∘180 - 58 = 122^\circ instead.

    So ∠ACB=58∘\angle ACB = 58^\circ.

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