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LearnQuantitative AptitudeGeometry & Mensuration

04.09 · Geometry & Mensuration

Mensuration: Surface Area & Volume

Elite lesson11 formulas10 questions

On the syllabus of

Elite lesson25 minEnglish

Formulas

At a glance 11 formulas

  1. 1Cuboidvolume lbh, surface 2(lb+bh+hl)\text{volume } lbh,\ \text{surface } 2(lb + bh + hl)l,b,h=edges; longest rod l2+b2+h2l, b, h = \text{edges};\ \text{longest rod } \sqrt{l^2 + b^2 + h^2}
  2. 2Cylinder, radius rvolume=πr2h, curved=2πrh\text{volume} = \pi r^2 h,\ \text{curved} = 2\pi r hh=height; total surface=2πr(r+h)h = \text{height; total surface} = 2\pi r(r + h)
  3. 3Cone, slant height lvolume=13πr2h, curved=πrl\text{volume} = \tfrac{1}{3}\pi r^2 h,\ \text{curved} = \pi r lr,h=radius, height; l=r2+h2r, h = \text{radius, height};\ l = \sqrt{r^2 + h^2}
  4. 4Sphere, radius rvolume=43πr3, surface=4πr2\text{volume} = \tfrac{4}{3}\pi r^3,\ \text{surface} = 4\pi r^2hemisphere: 23πr3, total surface 3πr2\text{hemisphere: } \tfrac{2}{3}\pi r^3,\ \text{total surface } 3\pi r^2
  5. 5Units and flow1 m3=1000 L, 1 L=1000 cm31\ \text{m}^3 = 1000\ \text{L},\ 1\ \text{L} = 1000\ \text{cm}^3pipe flow=πr2×speed, r=pipe radius\text{pipe flow} = \pi r^2 \times \text{speed},\ r = \text{pipe radius}
  6. 6Melting and recastingVolume stays the same and surface area does not: pieces = old volume ÷ volume of one new piece. Cancel π\pi and common factors before multiplying.
  7. 7Water displacedrise=solid’s volumevessel’s base area\text{rise} = \dfrac{\text{solid's volume}}{\text{vessel's base area}}
  8. 8Box from three facesvolume=xyz\text{volume} = \sqrt{xyz}x,y,z=face areas at one cornerx, y, z = \text{face areas at one corner}
  9. 9Rolling a sheetThe edge that goes round becomes the circumference 2πr2\pi r and the other edge the height. Both ways the curved surface is the whole sheet, but the volumes differ.
  10. 10Sector into a coner=θ360∘×R, l=Rr = \dfrac{\theta}{360^\circ} \times R,\ l = RR,θ=sector; r=base radius, l=slantR, \theta = \text{sector};\ r = \text{base radius},\ l = \text{slant}
  11. 11Similar conessmall volumebig volume=k3\dfrac{\text{small volume}}{\text{big volume}} = k^3k=height ratio; frustum=1−k3 of itk = \text{height ratio};\ \text{frustum} = 1 - k^3 \text{ of it}

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    A rectangular water tank is 2 m long, 1.5 m wide and 1.2 m deep. How many litres of water does it hold when full?

    Correct answer3,600 L

    Why

    Volume is length times breadth times height, and each cubic metre holds 1,000 litres.

    2×1.5×1.2=3.62 \times 1.5 \times 1.2 = 3.6 m³.

    3.6×1000=36003.6 \times 1000 = 3600, so the tank holds 3,600 L.

  2. Q2Easy

    A solid metal sphere of radius 6 cm is melted and recast into small solid cones, each with base radius 2 cm and height 3 cm. How many cones are made, assuming no metal is lost?

    Correct answer72

    Why

    Recasting keeps the volume, so divide the ball's volume by one cone's, with π\pi cancelled.

    Ball: 43×63=288\frac{4}{3} \times 6^3 = 288; one cone: 13×22×3=4\frac{1}{3} \times 2^2 \times 3 = 4.

    288÷4=72288 \div 4 = 72 cones.

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