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LearnQuantitative AptitudeArithmetic

01.01 · Arithmetic

Percentages

Open lesson10 formulas10 questions

On the syllabus of

Formulas

At a glance 10 formulas

  1. 1Percentage changechange %=new−oldold×100\text{change}\ \% = \dfrac{\text{new} - \text{old}}{\text{old}} \times 100
  2. 2Fraction to percent
    12\tfrac{1}{2}
    50%
    13\tfrac{1}{3}
    331333\tfrac{1}{3}%
    14\tfrac{1}{4}
    25%
    15\tfrac{1}{5}
    20%
    16\tfrac{1}{6}
    162316\tfrac{2}{3}%
    17\tfrac{1}{7}
    142714\tfrac{2}{7}%
    18\tfrac{1}{8}
    12.5%
    38\tfrac{3}{8}
    37.5%
    19\tfrac{1}{9}
    111911\tfrac{1}{9}%
    111\tfrac{1}{11}
    91119\tfrac{1}{11}%
    112\tfrac{1}{12}
    8138\tfrac{1}{3}%
    116\tfrac{1}{16}
    6.25%
  3. 3Multiplierx% up⇒×(1+x100)x\%\ \text{up} \Rightarrow \times\left(1 + \dfrac{x}{100}\right)x% down⇒×(1−x100)x\%\ \text{down} \Rightarrow \times\left(1 - \dfrac{x}{100}\right)
  4. 4More than, less thanx% more⇒less by x100+x×100%x\%\ \text{more} \Rightarrow \text{less by } \dfrac{x}{100 + x} \times 100\%x% less⇒more by x100−x×100%x\%\ \text{less} \Rightarrow \text{more by } \dfrac{x}{100 - x} \times 100\%
  5. 5Successive changenet %=a+b+ab100\text{net}\ \% = a + b + \dfrac{ab}{100}equal rise and fall: −a2100 %\text{equal rise and fall: } -\dfrac{a^2}{100}\,\%
  6. 6Three or more changesfinal=start×m1×m2×m3\text{final} = \text{start} \times m_1 \times m_2 \times m_3
  7. 7Price, use and spendmuse=mspendmpricem_{\text{use}} = \dfrac{m_{\text{spend}}}{m_{\text{price}}}same spend: price up x%⇒use down x100+x×100%\text{same spend: price up } x\% \Rightarrow \text{use down } \dfrac{x}{100 + x} \times 100\%
  8. 8Margin in pointstotal=leadgap in points×100\text{total} = \dfrac{\text{lead}}{\text{gap in points}} \times 100
  9. 9The part that staysnew total=unchanged partits new share\text{new total} = \dfrac{\text{unchanged part}}{\text{its new share}}
  10. 10Pass bothpass both=100−(x+y−z) %\text{pass both} = 100 - (x + y - z)\,\%

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    A pair of sneakers is repriced from ₹2,400 to ₹1,800 in a sale. By what percentage has the price fallen?

    Correct answer25%

    Why

    Percentage change always sits on the old price.

    The fall is 2400−1800=6002400 - 1800 = 600, and 6002400=14\frac{600}{2400} = \frac{1}{4}; dividing by 1800 instead gives the trap 331333\frac{1}{3}%.

    So the price has fallen by 25%.

  2. Q2Easy

    The price of a phone was increased by 20%, then reduced by 20%, and later increased by 10%. What is the net change in its price compared with the original price?

    Correct answer5.6% increase

    Why

    Pair the equal rise and fall first: +20+20% then −20-20% nets −202100=−4-\frac{20^2}{100} = -4%.

    Combine −4-4 and +10+10 with a+b+ab100a + b + \frac{ab}{100}: −4+10−0.4=5.6-4 + 10 - 0.4 = 5.6.

    So the phone ends up costing 5.6% more than at the start.

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