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01.03 · Arithmetic

Simple & Compound Interest

Elite lesson11 formulas10 questions

On the syllabus of

Elite lesson22 minEnglish

Formulas

At a glance 11 formulas

  1. 1Simple interestSI=P×R×T100SI = \dfrac{P \times R \times T}{100}total interest=(R×T)% of P\text{total interest} = (R \times T)\%\ \text{of } P
  2. 2SI from two amountsyearly SI=A2−A1T2−T1\text{yearly SI} = \dfrac{A_2 - A_1}{T_2 - T_1}P=A1−T1×yearly SIP = A_1 - T_1 \times \text{yearly SI}
  3. 3n times under SIR×T=(n−1)×100R \times T = (n - 1) \times 100doubles: R×T=100\text{doubles: } R \times T = 100
  4. 4Compound amountA=P(1+R100)nA = P\left(1 + \dfrac{R}{100}\right)^{n}2 years: CI=(2R+R2100)% of P\text{2 years: } CI = \left(2R + \dfrac{R^2}{100}\right)\%\ \text{of } P
  5. 5Half-yearly, quarterlyhalf-yearly: R2% for 2n periods\text{half-yearly: } \tfrac{R}{2}\%\ \text{for } 2n \text{ periods}quarterly: R4% for 4n periods\text{quarterly: } \tfrac{R}{4}\%\ \text{for } 4n \text{ periods}
  6. 62-year CI minus SICI−SI=P(R100)2CI - SI = P\left(\dfrac{R}{100}\right)^{2}=one year’s SI×R100= \text{one year's SI} \times \dfrac{R}{100}
  7. 73-year CI minus SICI−SI=P(R100)2(3+R100)CI - SI = P\left(\dfrac{R}{100}\right)^{2}\left(3 + \dfrac{R}{100}\right)
  8. 8CI amounts in GP1+R100=An+1An1 + \dfrac{R}{100} = \dfrac{A_{n+1}}{A_n}equal gaps: Ak2=P×A2k\text{equal gaps: } A_k^{2} = P \times A_{2k}
  9. 9Multiples under CIn× in T yrs⇒nk× in kT yrsn\times \text{ in } T \text{ yrs} \Rightarrow n^{k}\times \text{ in } kT \text{ yrs}
  10. 10Rate on a split (SI)R=P1R1+P2R2P1+P2R = \dfrac{P_1R_1 + P_2R_2}{P_1 + P_2}P1P2=R2−RR−R1\dfrac{P_1}{P_2} = \dfrac{R_2 - R}{R - R_1}
  11. 11Equal instalmentsprice=xm+xm2+⋯ , m=1+R100\text{price} = \dfrac{x}{m} + \dfrac{x}{m^{2}} + \cdots,\ m = 1 + \tfrac{R}{100}two instalments: x=price×m2m+1\text{two instalments: } x = \dfrac{\text{price} \times m^{2}}{m + 1}

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    Tara puts ₹20,000 in a bank deposit that pays 5% per annum compound interest, compounded annually. How much interest does she earn in 2 years?

    Correct answer₹2,050

    Why

    Two years of compound interest is two years of simple interest plus interest on the first year's interest.

    One year earns 5% of ₹20,000, which is ₹1,000, so two years give ₹2,000, and that first ₹1,000 earns 5% more: ₹50.

    So she earns ₹2,050 in interest.

  2. Q2Easy

    Asked in BBA DBE 2024

    The simple interest on a certain sum of money invested at 7.5%7.5\% per annum for 4 years is ₹243. What was the sum (in ₹) invested?

    Correct answer810

    Why

    Read simple interest as one total percent: 7.5×4=307.5 \times 4 = 30.

    So ₹243 is 30% of what was invested, and 243÷0.3=810243 \div 0.3 = 810.

    The sum invested was ₹810.

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