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01.07 · Arithmetic

Mixtures & Alligation

Elite lesson10 formulas10 questions

On the syllabus of

Elite lesson32 minEnglish

Formulas

At a glance 10 formulas

  1. 1Mean of a mixturemean=q1x1+q2x2q1+q2\text{mean} = \dfrac{q_1 x_1 + q_2 x_2}{q_1 + q_2}
  2. 2Alligation crossqcheapqdear=d−mm−c\dfrac{q_{\text{cheap}}}{q_{\text{dear}}} = \dfrac{d - m}{m - c}the mean m lies between c and d\text{the mean } m \text{ lies between } c \text{ and } d
  3. 3Balance the deviations∑qi (xi−m)=0\textstyle\sum q_i\,(x_i - m) = 0three or more items mixed to a mean m\text{three or more items mixed to a mean } m
  4. 4Topping up one partnew total=fixed partits new share\text{new total} = \dfrac{\text{fixed part}}{\text{its new share}}to add=new total−old total\text{to add} = \text{new total} - \text{old total}
  5. 5Strength p% to t%mixpure=100−tt−p\dfrac{\text{mix}}{\text{pure}} = \dfrac{100 - t}{t - p}water: mixwater=tp−t\text{water: } \dfrac{\text{mix}}{\text{water}} = \dfrac{t}{p - t}
  6. 6Drawing off a mixtureMixture drawn off leaves in its current ratio, so take each part out in proportion, then add what is poured in.
  7. 7Repeated replacementleft=V(1−xV)n\text{left} = V\left(1 - \dfrac{x}{V}\right)^{n}strength: cn=c0(1−xV)n\text{strength: } c_n = c_0\left(1 - \dfrac{x}{V}\right)^{n}
  8. 8Cost before profitmean cost=100×SP100+g\text{mean cost} = \dfrac{100 \times SP}{100 + g}
  9. 9Water costs nothingwatermilk=g100\dfrac{\text{water}}{\text{milk}} = \dfrac{g}{100}mix sold at milk’s cost price, gain g%\text{mix sold at milk's cost price, gain } g\%
  10. 10Alloys and ratiosTurn each ratio into the share of one metal (5 : 3 is 58\tfrac{5}{8} copper), then alligate the shares, never the ratios.

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    A school lab mixes 6 litres of a 30% acid solution with 4 litres of a 55% acid solution. What is the strength of the mixture?

    Correct answer40%

    Why

    Strength of a mix is a weighted mean, so weight each strength by its litres.

    Acid is 0.3×6+0.55×4=1.8+2.2=40.3 \times 6 + 0.55 \times 4 = 1.8 + 2.2 = 4 litres in 10 litres; the plain average 42.5% forgets there is more of the weak one.

    So the mixture is 40% acid.

  2. Q2Easy

    Asked in IPMAT Indore 2020

    Fifty litres of a mixture of milk and water contains 30 percent of water. This mixture is added to eighty litres of another mixture of milk and water that contains 20 percent of water. Then, how many litres of water should be added to the resulting mixture to obtain a final mixture that contains 25 percent of water?

    Correct answer2

    Why

    Follow the milk, since pouring in water leaves it untouched.

    Milk is 0.7×50+0.8×80=35+64=990.7 \times 50 + 0.8 \times 80 = 35 + 64 = 99 litres, and at 25% water it has to be three quarters of the final mix: 99÷0.75=13299 \div 0.75 = 132 litres.

    The two mixtures make 130 litres, so 2 litres of water go in.

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