Learn/Quantitative Aptitude/Algebra
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Elite lesson·38 minHinglishFormulas
At a glance 11 formulas
- 1General termTr+1=(rn)an−rbrin (a+b)n, r=0,1,…,n (n+1 terms)
- 2Middle termn even: T2n+1n odd: T2n+1 and T2n+3
- 3Symmetry(rn)=(n−rn)the largest (rn) is the middle one
- 4Term independent of xWrite the power of x in Tr+1 and set it to 0 (or to k for the xk term). If no whole-number r fits, there is no such term.
- 5Sum of coefficientssum of coefficients of f(x)=f(1)(0n)+(1n)+⋯+(nn)=2n
- 6Even and odd powerseven powers of f(x)=2f(1)+f(−1)odd powers=2f(1)−f(−1), constant=f(0)
- 7Weighted sum∑rr(rn)=n2n−1since r(rn)=n(r−1n−1)
- 8Neighbouring coefficients(rn)÷(r−1n)=rn−r+1
- 9Combine before expandingMultiply brackets first when they pair up: (1+x)n(1−x)n=(1−x2)n, so only even powers of x survive.
- 10Remainders(1+m)n=1+nm+(multiple of m2)so (1+m)n÷m2 leaves what 1+nm leaves
- 11Rational termsIn (pA+qB)n, with no perfect powers inside the roots, Tr+1 is rational exactly when p divides n−r and q divides r.
Test yourself
Q1Easy
What is the coefficient of x2 in the expansion of (1+2x)6?
Correct answer·60
Why
General term: Tr+1=(r6)(2x)r, and x2 needs r=2.
The coefficient is (26)×22=15×4 (leaving out the 22 gives the trap 15).
So the coefficient of x2 is 60.
Q2Easy
What is the sum of all the coefficients in the expansion of (2x−3y)7?
Correct answer·−1
Why
Sum of coefficients: put every variable equal to 1.
That gives (2−3)7=(−1)7; dropping the minus sign would give the trap 57=78125.
So the coefficients add up to −1.
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