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03.10 · Algebra

Maximum & Minimum Values

Elite lesson11 formulas10 questions

On the syllabus of

Elite lesson19 minEnglish

Formulas

At a glance 11 formulas

  1. 1Vertexax2+bx+c: extreme at x=−b2aax^2 + bx + c:\ \text{extreme at } x = -\dfrac{b}{2a}a>0: least;a<0: greatesta > 0:\ \text{least};\quad a < 0:\ \text{greatest}
  2. 2Extreme valuevalue=c−b24a\text{value} = c - \dfrac{b^2}{4a}=4ac−b24a for ax2+bx+c= \dfrac{4ac - b^2}{4a} \text{ for } ax^2 + bx + c
  3. 3Squares are never negative(x−p)2+(y−q)2+k≥k(x - p)^2 + (y - q)^2 + k \ge kleast value k at x=p, y=q\text{least value } k \text{ at } x = p,\ y = q
  4. 4Whole numbers onlyIf xx must be a whole number, check the whole numbers on either side of −b2a-\frac{b}{2a} and keep the better one.
  5. 5Flip a reciprocalf>0: greatest kf=kleast f (k>0)f > 0:\ \text{greatest } \dfrac{k}{f} = \dfrac{k}{\text{least } f} \ (k > 0)
  6. 6Fixed sumx+y=S⇒xy≤S24x + y = S \Rightarrow xy \le \dfrac{S^2}{4}greatest when x=y=S2\text{greatest when } x = y = \tfrac{S}{2}
  7. 7Fixed productx+kx≥2k (x,k>0)x + \dfrac{k}{x} \ge 2\sqrt{k} \ (x, k > 0)xy=P⇒x+y≥2P (x,y>0)xy = P \Rightarrow x + y \ge 2\sqrt{P} \ (x, y > 0)
  8. 8Unequal powersx+y=S: xmyn greatest at xm=ynx + y = S:\ x^m y^n \text{ greatest at } \dfrac{x}{m} = \dfrac{y}{n}a+b+c3≥abc3 (a,b,c>0)\dfrac{a + b + c}{3} \ge \sqrt[3]{abc} \ (a, b, c > 0)
  9. 9Fixed fenceperimeter P: square, area P216\text{perimeter } P:\ \text{square, area } \dfrac{P^2}{16}wall as one side, fence L: area L28\text{wall as one side, fence } L:\ \text{area } \dfrac{L^2}{8}
  10. 10Rectangle in a triangleThe largest rectangle with a corner at a right triangle's right angle takes half of each leg, and covers half the triangle's area.
  11. 11A straight-line conditionax+by=c⇒least x2+y2=c2a2+b2ax + by = c \Rightarrow \text{least } x^2 + y^2 = \dfrac{c^2}{a^2 + b^2}or substitute for one variable and use the vertex\text{or substitute for one variable and use the vertex}

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    Two positive numbers add up to 30. What is the greatest possible value of their product?

    Correct answer225

    Why

    For a fixed sum, the product is greatest when the two parts are equal.

    Split 30 as 15+1515 + 15; any other split, such as 12×18=21612 \times 18 = 216, gives less.

    So the greatest product is 15×1515 \times 15, which is 225.

  2. Q2Easy

    A startup models its daily net engagement score as E=−2x2+56x−180E=-2x^2+56x-180, where xx is the number of influencer posts promoted in a day. What is the maximum possible value of EE?

    Correct answer212

    Why

    Use the peak-value formula c−b24ac - \frac{b^2}{4a}; the −2x2-2x^2 makes the vertex a maximum.

    −180−5624(−2)=−180+31368=−180+392-180 - \frac{56^2}{4(-2)} = -180 + \frac{3136}{8} = -180 + 392.

    So the greatest value of EE is 212.

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