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03.08 · Algebra

Logarithms

Elite lesson13 formulas10 questions

On the syllabus of

Elite lesson31 minEnglish

Formulas

At a glance 13 formulas

  1. 1Definitionlog⁡ax=y  ⟺  ay=x\log_a x = y \iff a^y = xa>0, a≠1, x>0a > 0,\ a \ne 1,\ x > 0
  2. 2Values to knowlog⁡a1=0,log⁡aa=1\log_a 1 = 0,\quad \log_a a = 1alog⁡ax=xa^{\log_a x} = x
  3. 3Product and powerlog⁡mn=log⁡m+log⁡n\log mn = \log m + \log nlog⁡mk=klog⁡m\log m^{k} = k\log m
  4. 4Quotientlog⁡mn=log⁡m−log⁡n\log \dfrac{m}{n} = \log m - \log nlog⁡(m+n)≠log⁡m+log⁡n\log (m + n) \ne \log m + \log n
  5. 5Change of baselog⁡ab=log⁡blog⁡a\log_a b = \dfrac{\log b}{\log a}log⁡ab×log⁡ba=1\log_a b \times \log_b a = 1
  6. 6Power in the baselog⁡akx=1k log⁡ax\log_{a^k} x = \dfrac{1}{k}\,\log_a xlog⁡akxm=mk log⁡ax\log_{a^k} x^{m} = \dfrac{m}{k}\,\log_a x
  7. 7Chain of logslog⁡ab×log⁡bc×log⁡cd=log⁡ad\log_a b \times \log_b c \times \log_c d = \log_a d
  8. 8The flipalog⁡bc=clog⁡baa^{\log_b c} = c^{\log_b a}
  9. 9Nested logsPeel from the outside with log⁡ay=k⇒y=ak\log_a y = k \Rightarrow y = a^k: log⁡2(log⁡3y)=1\log_2(\log_3 y) = 1 gives log⁡3y=2\log_3 y = 2, so y=9y = 9.
  10. 10Check the domainEvery log needs a positive input and a positive base other than 1. Solve first, then throw out any root that makes an input 0 or negative.
  11. 11Log inequalitya>1: log⁡ax>log⁡ay  ⟺  x>y>0a > 1:\ \log_a x > \log_a y \iff x > y > 00<a<1: log⁡ax>log⁡ay  ⟺  0<x<y0 < a < 1:\ \log_a x > \log_a y \iff 0 < x < y
  12. 12Quadratic in a logWith log⁡ax\log_a x and log⁡xa\log_x a together, put t=log⁡axt = \log_a x, so log⁡xa=1t\log_x a = \frac{1}{t}. If the roots are t1,t2t_1, t_2, the solutions xx multiply to at1+t2a^{t_1 + t_2}.
  13. 13Number of digitsdigits in N=⌊log⁡10N⌋+1\text{digits in } N = \lfloor \log_{10} N \rfloor + 1whole N≥1; e.g. log⁡10250≈15.05, so 16 digits\text{whole } N \ge 1;\ \text{e.g. } \log_{10} 2^{50} \approx 15.05,\ \text{so 16 digits}

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    If log⁡x64=3\log_x 64 = 3, what is xx?

    Correct answer4

    Why

    Turn the log into a power: log⁡x64=3\log_x 64 = 3 means x3=64x^3 = 64.

    43=644^3 = 64; taking the square root gives the trap 8, and dividing 64 by 3 gives 643\frac{64}{3}.

    So x=4x = 4.

  2. Q2Easy

    Solve for xx: log⁡2(x−3)+log⁡2(x+1)=5\log_2(x - 3) + \log_2(x + 1) = 5.

    Correct answer7

    Why

    Join the two logs into one, then rewrite it as a power of 2.

    (x−3)(x+1)=25=32(x - 3)(x + 1) = 2^5 = 32 means x2−2x−35=0x^2 - 2x - 35 = 0, whose roots are 7 and −5-5.

    Only 7 keeps both inputs positive, so x=7x = 7.

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