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03.12 · Algebra

Geometric Progression

Elite lesson11 formulas10 questions

On the syllabus of

Elite lesson22 minEnglish

Formulas

At a glance 11 formulas

  1. 1nth termTn=a r n−1T_n = a\,r^{\,n-1}a=first term, r=common ratioa = \text{first term},\ r = \text{common ratio}
  2. 2Sum of n termsSn=a rn−1r−1,r≠1S_n = a\,\dfrac{r^n - 1}{r - 1},\quad r \ne 1doubling from 1: 1+2+⋯+2n−1=2n−1\text{doubling from 1: } 1 + 2 + \dots + 2^{n-1} = 2^n - 1
  3. 3Three in a rowb2=acb^2 = aca,b,c consecutive; in an AP: b=a+c2a, b, c \text{ consecutive; in an AP: } b = \tfrac{a + c}{2}
  4. 4Three unknown termsar, a, ar\dfrac{a}{r},\ a,\ arproduct=a3, so a given product fixes a\text{product} = a^3 \text{, so a given product fixes } a
  5. 5The infinite GPS∞=a1−r,∣r∣<1S_\infty = \dfrac{a}{1 - r},\quad |r| < 1∣r∣≥1: the sum never settles|r| \ge 1 \text{: the sum never settles}
  6. 6Alternating signsa−ar+ar2−⋯=a1+ra - ar + ar^2 - \dots = \dfrac{a}{1 + r}0<r<10 < r < 1
  7. 7Negative ratioWith r<0r < 0 the running total swings above and below S∞S_\infty, so a partial sum can be bigger than the whole infinite sum.
  8. 8Bouncing balldistance=h 1+r1−r\text{distance} = h\,\dfrac{1 + r}{1 - r}h=drop height, r=rebound fractionh = \text{drop height},\ r = \text{rebound fraction}
  9. 9Blocks of k termsS2k=Sk (1+rk)S_{2k} = S_k\,(1 + r^k)the next k terms=rk×the first k\text{the next } k \text{ terms} = r^k \times \text{the first } k
  10. 10Repeating patternIf the signs or terms repeat every kk terms, add each group of kk: the groups form a GP with ratio rkr^k.
  11. 11Pairs from the endsTk×Tn+1−k=a lT_k \times T_{n+1-k} = a\,lS÷R=al (S=sum, R=sum of reciprocals), product=(al)n/2, l=last termS \div R = al\ (S = \text{sum},\ R = \text{sum of reciprocals}),\ \text{product} = (al)^{n/2},\ l = \text{last term}

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    What is the 8th term of the geometric progression 96,48,24,…96, 48, 24, \dots?

    Correct answer34\frac{3}{4}

    Why

    The nnth term is the first term times the ratio, n−1n - 1 times over.

    The ratio is 12\frac{1}{2}, so T8=96×(12)7=96128T_8 = 96 \times \left(\frac{1}{2}\right)^7 = \frac{96}{128}.

    So the 8th term is 34\frac{3}{4}.

  2. Q2Easy

    The numbers xx, x+4x + 4 and x+10x + 10 are three consecutive terms of a geometric progression. What is the next term of the progression?

    Correct answer27

    Why

    Three in a row: the middle term squared equals the product of the other two.

    (x+4)2=x(x+10)(x + 4)^2 = x(x + 10) gives 8x+16=10x8x + 16 = 10x, so x=8x = 8 and the terms are 8, 12, 18.

    The ratio is 32\frac{3}{2}, so the next term is 18×32=2718 \times \frac{3}{2} = 27 (adding a next gap of 8 gives the trap 26).

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