Learn/ Quantitative Aptitude / Algebra
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20 min Formulas At a glance 12 formulas
1 Same base a m × a n = a m + n a^m \times a^n = a^{m+n} a m × a n = a m + n a m a n = a m − n \dfrac{a^m}{a^n} = a^{m-n} a n a m = a m − n 2 Power of a power ( a m ) n = a m n (a^m)^n = a^{mn} ( a m ) n = a mn ( a b ) n = a n b n (ab)^n = a^n b^n ( ab ) n = a n b n 3 Zero and negative powers a 0 = 1 , a − n = 1 a n a^0 = 1,\ a^{-n} = \dfrac{1}{a^n} a 0 = 1 , a − n = a n 1 ( a b ) − n = ( b a ) n \left(\dfrac{a}{b}\right)^{-n} = \left(\dfrac{b}{a}\right)^{n} ( b a ) − n = ( a b ) n 4 Fractional powers a m n = ( a n ) m a^{\frac{m}{n}} = \left(\sqrt[n]{a}\right)^{m} a n m = ( n a ) m a × b = a b \sqrt{a} \times \sqrt{b} = \sqrt{ab} a × b = ab 5 Equal powers a x = a y ⇒ x = y a^x = a^y \Rightarrow x = y a x = a y ⇒ x = y when a > 0 , a ≠ 1 \text{when } a > 0,\ a \ne 1 when a > 0 , a = 1 6 Rationalise 1 a + b = a − b a − b \dfrac{1}{\sqrt{a} + \sqrt{b}} = \dfrac{\sqrt{a} - \sqrt{b}}{a - b} a + b 1 = a − b a − b 1 n + n + 1 = n + 1 − n \dfrac{1}{\sqrt{n} + \sqrt{n+1}} = \sqrt{n+1} - \sqrt{n} n + n + 1 1 = n + 1 − n 7 Root of a surd a + b + 2 a b = a + b \sqrt{a + b + 2\sqrt{ab}} = \sqrt{a} + \sqrt{b} a + b + 2 ab = a + b a + b − 2 a b = a − b , a > b \sqrt{a + b - 2\sqrt{ab}} = \sqrt{a} - \sqrt{b},\ a > b a + b − 2 ab = a − b , a > b 8 Reciprocal surds a 2 − b = 1 ⇒ 1 a + b = a − b a^2 - b = 1 \Rightarrow \dfrac{1}{a + \sqrt{b}} = a - \sqrt{b} a 2 − b = 1 ⇒ a + b 1 = a − b e.g. ( 2 + 3 ) ( 2 − 3 ) = 1 \text{e.g. } (2 + \sqrt{3})(2 - \sqrt{3}) = 1 e.g. ( 2 + 3 ) ( 2 − 3 ) = 1 9 Factor the smallest power Take out the smallest power: 3 n + 2 + 3 n = 3 n ( 9 + 1 ) 3^{n+2} + 3^{n} = 3^{n}(9 + 1) 3 n + 2 + 3 n = 3 n ( 9 + 1 ) . The unknown power then stands alone, or cancels. 10 Compare roots Raise every root to the LCM of the root indices, then compare whole numbers: 2 \sqrt{2} 2 vs 3 3 \sqrt[3]{3} 3 3 becomes 2 3 = 8 2^3 = 8 2 3 = 8 vs 3 2 = 9 3^2 = 9 3 2 = 9 . 11 Common value a x = b y = k ⇒ a = k 1 x , b = k 1 y a^x = b^y = k \Rightarrow a = k^{\frac{1}{x}},\ b = k^{\frac{1}{y}} a x = b y = k ⇒ a = k x 1 , b = k y 1 if also c z = k and c = a p b q : 1 z = p x + q y \text{if also } c^z = k \text{ and } c = a^p b^q:\ \tfrac{1}{z} = \tfrac{p}{x} + \tfrac{q}{y} if also c z = k and c = a p b q : z 1 = x p + y q 12 Power equal to 1 a b = 1 a^b = 1 a b = 1 in three cases: a = 1 a = 1 a = 1 ; b = 0 b = 0 b = 0 with a ≠ 0 a \ne 0 a = 0 ; a = − 1 a = -1 a = − 1 with b b b an even integer. Check all three and count repeats once.Test yourself Q1 Easy
What is the value of 9 4 × 27 2 3 11 \dfrac{9^{4} \times 27^{2}}{3^{11}} 3 11 9 4 × 2 7 2 ?
A 1 B 3 C 9 D 27
Correct answer· 27
Why
Write every number as a power of 3.
9 4 = 3 8 9^4 = 3^8 9 4 = 3 8 and 27 2 = 3 6 27^2 = 3^6 2 7 2 = 3 6 , so the top is 3 14 3^{14} 3 14 , and 3 14 ÷ 3 11 = 3 3 3^{14} \div 3^{11} = 3^{3} 3 14 ÷ 3 11 = 3 3 .
So the value is 27.
Q2 Easy
If 2 x + y = 4 x − y = 32 2^{x+y} = 4^{x-y} = \sqrt{32} 2 x + y = 4 x − y = 32 , then $xy = $ ___.
A 75 32 \frac{75}{32} 32 75 B 75 64 \frac{75}{64} 64 75 C 75 16 \frac{75}{16} 16 75 D 75 128 \frac{75}{128} 128 75
Correct answer· 75 64 \frac{75}{64} 64 75
Why
Put everything on base 2: 4 x − y = 2 2 x − 2 y 4^{x-y} = 2^{2x - 2y} 4 x − y = 2 2 x − 2 y and the root of 32 is 2 2.5 2^{2.5} 2 2.5 .
Matching the powers, x + y = 2.5 x + y = 2.5 x + y = 2.5 and x − y = 1.25 x - y = 1.25 x − y = 1.25 , which puts x x x at 1.875 1.875 1.875 and y y y at 0.625 0.625 0.625 .
Their product is 15 8 × 5 8 \frac{15}{8} \times \frac{5}{8} 8 15 × 8 5 , which is 75 64 \frac{75}{64} 64 75 .
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