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03.07 · Algebra

Modulus Equations & Functions

Elite lesson11 formulas10 questions

On the syllabus of

Elite lesson1 h 10 minHindi

Formulas

At a glance 11 formulas

  1. 1Definition∣x∣=x (x≥0),∣x∣=−x (x<0)|x| = x \ (x \ge 0),\quad |x| = -x \ (x < 0)x2=∣x∣,∣x∣2=x2\sqrt{x^2} = |x|,\quad |x|^2 = x^2
  2. 2Distance∣x−a∣=distance from x to a|x - a| = \text{distance from } x \text{ to } a∣a−b∣=∣b−a∣|a - b| = |b - a|
  3. 3Modulus equation∣x−a∣=b⇒x=a±b (b≥0)|x - a| = b \Rightarrow x = a \pm b \ (b \ge 0)b<0⇒no solutionb < 0 \Rightarrow \text{no solution}
  4. 4Less than, more than∣x−a∣<b  ⟺  a−b<x<a+b|x - a| < b \iff a - b < x < a + b∣x−a∣>b  ⟺  x<a−b or x>a+b|x - a| > b \iff x < a - b \text{ or } x > a + b
  5. 5Bars on both sides∣A∣=∣B∣  ⟺  A=±B|A| = |B| \iff A = \pm B∣A∣<∣B∣  ⟺  A2<B2 (any A,B)|A| < |B| \iff A^2 < B^2 \ (\text{any } A, B)
  6. 6Critical pointsMark where each bar's inside is 0, split the number line there, and drop the bars piece by piece. Keep only answers that lie in their own piece.
  7. 7Sum of two distances∣x−a∣+∣x−b∣≥∣a−b∣|x - a| + |x - b| \ge |a - b|equal for every x between a and b\text{equal for every } x \text{ between } a \text{ and } b
  8. 8Median rule∣x−a1∣+∣x−a2∣+⋯+∣x−an∣|x - a_1| + |x - a_2| + \dots + |x - a_n| is least at the median of the aa's; with an even count, anywhere between the middle two.
  9. 9Triangle inequality∣a+b∣≤∣a∣+∣b∣|a + b| \le |a| + |b|equal exactly when ab≥0\text{equal exactly when } ab \ge 0
  10. 10Graph of |f(x)|Draw y=f(x)y = f(x), then flip every part below the xx-axis up. The solutions of ∣f(x)∣=k|f(x)| = k are where the line y=ky = k cuts this graph.
  11. 11Diamond area∣x−p∣+∣y−q∣=c: area 2c2|x - p| + |y - q| = c:\ \text{area } 2c^2a∣x∣+b∣y∣=c: area 2c2ab (a,b,c>0)a|x| + b|y| = c:\ \text{area } \dfrac{2c^2}{ab} \ (a, b, c > 0)

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    Find the real number xx for which ∣x+2∣=∣x−6∣|x + 2| = |x - 6|.

    Correct answer2

    Why

    Read both bars as distances: xx is as far from −2-2 as from 6.

    That point is the midpoint, −2+62\frac{-2 + 6}{2}; the half-gap 4 is the distance to each end, not the point.

    So x=2x = 2.

  2. Q2Easy

    Asked in BBA DBE 2024

    Find the sum of the smallest value and the greatest value of xx that satisfy the inequality ∣5x+5∣−8≤17|5x + 5| - 8 \le 17.

    Correct answer−2-2

    Why

    Clear the constant, then read the bar as a distance.

    ∣5x+5∣≤25|5x + 5| \le 25 means ∣x+1∣≤5|x + 1| \le 5, so xx runs from −6-6 to 44.

    Adding the two ends gives −2-2.

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