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03.13 · Algebra

Special Series & Sums

Elite lesson12 formulas10 questions

On the syllabus of

Elite lesson25 minEnglish

Formulas

At a glance 12 formulas

  1. 1First n numbers1+2+⋯+n=n(n+1)21 + 2 + \dots + n = \dfrac{n(n + 1)}{2}
  2. 2Sum of squares12+22+⋯+n2=n(n+1)(2n+1)61^2 + 2^2 + \dots + n^2 = \dfrac{n(n+1)(2n+1)}{6}
  3. 3Sum of cubes13+⋯+n3=[n(n+1)2]21^3 + \dots + n^3 = \left[\dfrac{n(n + 1)}{2}\right]^2=(1+2+⋯+n)2= (1 + 2 + \dots + n)^2
  4. 4Odd and even numbers1+3+⋯+(2n−1)=n21 + 3 + \dots + (2n - 1) = n^22+4+⋯+2n=n(n+1)2 + 4 + \dots + 2n = n(n + 1)
  5. 5Sum not from 1Tk+⋯+Tn=Sn−Sk−1T_k + \dots + T_n = S_n - S_{k-1}Sn=sum of the first n termsS_n = \text{sum of the first } n \text{ terms}
  6. 6Split the general termTk=k2+k⇒∑Tk=∑k2+∑kT_k = k^2 + k \Rightarrow \textstyle\sum T_k = \sum k^2 + \sum k1⋅2+2⋅3+⋯+n(n+1)=n(n+1)(n+2)31 \cdot 2 + 2 \cdot 3 + \dots + n(n + 1) = \tfrac{n(n+1)(n+2)}{3}
  7. 7Gaps that grow evenlyIf the gaps between terms grow by a fixed cc, then Tn=c2n2+pn+qT_n = \frac{c}{2}n^2 + pn + q; find pp and qq from T1T_1 and T2T_2, then sum with the standard sums.
  8. 8Products of pairs∑i<jxixj=(∑x)2−∑x22\textstyle\sum_{i<j} x_i x_j = \dfrac{(\sum x)^2 - \sum x^2}{2}each pair of different x’s counted once\text{each pair of different } x\text{'s counted once}
  9. 9Telescoping sum1k(k+d)=1d(1k−1k+d)\dfrac{1}{k(k + d)} = \dfrac{1}{d}\left(\dfrac{1}{k} - \dfrac{1}{k + d}\right)only the first and last pieces survive\text{only the first and last pieces survive}
  10. 10Telescoping productFactor each term into neighbouring brackets, write out the first two and the last two terms, and keep only what is left after the cancelling.
  11. 11Odd terms from allIf the even-kk terms are a fixed multiple of the whole series, the odd-kk terms are the rest: ∑1(2k)2=14∑1k2\sum \frac{1}{(2k)^2} = \frac{1}{4} \sum \frac{1}{k^2}.
  12. 12AGP to infinityS∞=a1−r+dr(1−r)2S_\infty = \dfrac{a}{1 - r} + \dfrac{dr}{(1 - r)^2}a, (a+d)r, (a+2d)r2,…, ∣r∣<1a,\ (a + d)r,\ (a + 2d)r^2, \dots,\ |r| < 1

Test yourself

10 questions · 3 easy · 4 medium · 3 hard

Tap an option to answer. The first tap counts.

  1. Q1Easy

    What is the sum of all the odd numbers from 1 to 59?

    Correct answer900

    Why

    The first nn odd numbers always add up to n2n^2.

    59 is the 30th odd number, since 59+12=30\frac{59 + 1}{2} = 30.

    So the sum is 302=90030^2 = 900.

  2. Q2Easy

    What is the value of 13+23+33+⋯+1031^3 + 2^3 + 3^3 + \dots + 10^3?

    Correct answer3025

    Why

    The first nn cubes add up to the square of 1+2+⋯+n1 + 2 + \dots + n.

    1+2+⋯+10=551 + 2 + \dots + 10 = 55.

    So the cubes add up to 552=302555^2 = 3025.

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